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A projectile is launched at an angle α from the edge of a cliff of height H above sea level. If it falls
into the sea a distance D from the base of the cliff, prove that its maximum height above sea level is
H + [(Dtan α)^2]/4(H + Dtan α)
Newtons equations of linear motion in the i/j plane.
Well, I understand that the max height is at a height H + (something) with that something being Sjmax, when Vj=0.
Ive got my Sjmax = (usin α)^2/ 2g
This is where i get a little stuck... I've tried a couple of things but the fact that its a cliff is making my reasoning wrong, if it wasnt a cliff, you could also say that the max vertical height is obtained when the horizontal displacement is D/2, the christmas break has made the old mind a little blunt... Any hints? Thanks so much in advance.
into the sea a distance D from the base of the cliff, prove that its maximum height above sea level is
H + [(Dtan α)^2]/4(H + Dtan α)
Newtons equations of linear motion in the i/j plane.
Well, I understand that the max height is at a height H + (something) with that something being Sjmax, when Vj=0.
Ive got my Sjmax = (usin α)^2/ 2g
This is where i get a little stuck... I've tried a couple of things but the fact that its a cliff is making my reasoning wrong, if it wasnt a cliff, you could also say that the max vertical height is obtained when the horizontal displacement is D/2, the christmas break has made the old mind a little blunt... Any hints? Thanks so much in advance.