- #1
Chandasouk
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Homework Statement
A firefighter d=50 m away from a burning building directs a stream of water from a fire hose at an angle of θ=30° above the horizontal. The speed of the water stream is 40 m/s.
a)
What is the maximum height in the air that the water reaches?
b)
At what height h will the water strike the building?
I found the Velocity for the horizontal component
Vx = cos30*40=34.64m/s
and the vertical component Vy= sin30*40 = 20m/s
For part a, is the height 10.2m?
I did
[tex]\Delta[/tex]X=Vx*t
50m=34.64m/s*t
t=1.44 seconds
then plugged that in the equation
[tex]\Delta[/tex]y=Vy*T+1/2at^2
which at max height is [tex]\Delta[/tex]y=1/2at^2
1/2(-9.8)(1.44)^2 = 10.2mOr would that be the height of the building?