- #1
KiNGGeexD
- 317
- 1
I have another question for you guys:)! I have solved something and I just want to know if my method is ok!A ball of mass m is ejected from a mortar at speed v and angle θ to the horizontal, at the top of its trajectory it explodes into two equal pieces of mass m/2 and one drops vertically what is the velocity of the other right after the explosion?
The first thing I done was components of velocity
v(x)= (vcosθ)
v(y)=(vsinθ)
Then calculated momentum before and made it equal to momentum after as there was no external force so momentum is conserved
Although I used (vcosθ)i+(vsinθ)j
And when cancelling out I got my final answer as
v=gt/2sinθ
Is my methodology correct or should I go about this problem in a different wayCheers guys!
The first thing I done was components of velocity
v(x)= (vcosθ)
v(y)=(vsinθ)
Then calculated momentum before and made it equal to momentum after as there was no external force so momentum is conserved
Although I used (vcosθ)i+(vsinθ)j
And when cancelling out I got my final answer as
v=gt/2sinθ
Is my methodology correct or should I go about this problem in a different wayCheers guys!