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bonbloc
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Projectile Motion - motion on a horizontal surface please help!
Isaac Newton shot a dirty snowball 76m across a horizontal field. It passed directly over Edmund Haley's head, and was in the air for 7.6s. How high did it get above the field? Answer in m.
Δd = V1(Δt) + 1/2(g)(Δt)^2
and i think some projectile motion equations, not sure if those will help.
since at maximum height the velocity will be zero i tried this:
Δd = 0m/s(Δt) - 1/2(9.8m/s^2)(7.6s)^2
Δd = 283m
but this is not the right answer, so i would appreciate it if someone could help me with this.
Thank you.
Homework Statement
Isaac Newton shot a dirty snowball 76m across a horizontal field. It passed directly over Edmund Haley's head, and was in the air for 7.6s. How high did it get above the field? Answer in m.
Homework Equations
Δd = V1(Δt) + 1/2(g)(Δt)^2
and i think some projectile motion equations, not sure if those will help.
The Attempt at a Solution
since at maximum height the velocity will be zero i tried this:
Δd = 0m/s(Δt) - 1/2(9.8m/s^2)(7.6s)^2
Δd = 283m
but this is not the right answer, so i would appreciate it if someone could help me with this.
Thank you.