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songoku
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Homework Statement
As shown in the figure below, small object A is projected upward along a smooth slope forming angle α with the horizontal plane, with initial speed v0 in the direction of angle θ from the horizontal within the slope’s plane. The object continues to travel along the surface of the slope. Let us denote as h the maximum height that A attains on the slope, where height is measured vertically from A’s starting point. Find v0
Homework Equations
projectile motion
The Attempt at a Solution
I interpret the question as projectile motion with total angle (α + θ) with respect to horizontal plane.
At maximum height, vertical speed is zero, so:
vy2 = voy2 - 2gh
v0 = √(2gh) / (sin (α + θ))
But the answer is v0 = √(2gh) / (sin θ)
Do I interpret the question wrongly? Or there is mistake in my working?
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