- #1
Touran Khan
- 16
- 2
Homework Statement
A student in the back row of class fires a pea shooter in an attempt to hit the blackboard. The student fires it a distance of 23m from his seat to hit the black board. The pea hits the board after 1.4 seconds at a location 9.3 meters below the ceiling. The pea is fired from a vertical position, 3.1m below the ceiling. Find the maximum height of the pea in its trajectory
Homework Equations
u = initial velocity
x = ut
y = ut + 1/2at2
v = u + at
v2 = u2 + 2ad
The Attempt at a Solution
Firstly, attempting to find initial velocity for y direction:
y direction:
d = 9.3 - 3.1 = 6.2 m
u = vsintheta
a = - 9.8 m/s2
t = 1.4 s
Using equations of motion: 6.2 = vsintheta + 1/2(-9.8)(1.4)2
vsintheta = 15.08 m/s
Finding max distance:
u = 15.08 m/s
v = 0 m/s
a = - 9.8 m/s
0 = 15.082 + 2(-9.8)(d)
d = 12.74 m
I feel like I've done something wrong? Not entirely sure, though. Don't have the answer to the questions. Thanks for the help!
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