- #1
EHogeberg
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Homework Statement
A projectile is fired with an initial speed of 16.0 m/s at an angle of 45.0^\circ above the horizontal. The object hits the ground 9.00 s later.
What is the direction (below +x) of the projectile's velocity at the instant it hits the ground?
Vo=16m/s
a=-g
θ=45
Tf=9 seconds
magnitude of velocity an instant before it hits the ground: 77.7 m/s
max height: 301.53 m/s
Homework Equations
-gsin(θ)
Vxf=Vxi+a(tf-ti)
Xf=Xi+Vxi(tf-ti) + 1/2 A(tf-ti)^2
Vxf^2=Vxi^2+2a(Xf-Xi)
Vyf=Vyi+a(tf-ti)
Yf=yi+Vyi(tf-ti) + 1/2 A(tf-ti)^2
Vyf^2=Vyi^2+2a(Yf-Yi)
The Attempt at a Solution
I got 45 degrees and I got that from finding the xcomponents and ycomponents