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SEZHUR
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Homework Statement
THIS PROBLEM HAS BEEN SOLVED
Quoted verbatim: A ship has maneuvered to within 2500m of an 1800m high mountainous island, as shown below. If the shoreline on the other side of the island is horizontally 300m from the base, what are the distances from the shore at which another ship can be safe from the guns of the first ship?
[Also, the ships gun fires at 250m/s]
Homework Equations
The Attempt at a Solution
What i figure is that we need to find the two angles that will hit the island at it's apex, discern which of the two arc's has it's apex before the island (so the shot will land as close to the island as possible), find out where that arc lands and subtract 2800 for the final answer. The problem comes in when i have to solve for the angle (my trig's not so good).
First i find time in terms of the range and initial velocity:
d=vt
2500=250cos(x)t
t=10/cos(x)
then substitute into the equation for the height
d=vt+(at^2)/2
1800=(250sin(x))(10/cos(x)) - 4.9(10/cos(x))^2
2500tan(x) - 490/cos(x)^2 - 1800 = 0
This is where i get stuck. I've already posted just this last part on a math forum to no avail, so I'm trying here now because I'm beginning to grow suspicious of my method. It seems to me that the trig question is too hard (based on the delay in response from the math forum) for the 100 level paper I'm doing.
Any help is welcome.
Thanks
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