- #1
prohme
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Homework Statement
A movie set requires a stunt man to jump across a 40m wide river on a motorcycle. The takeoff ramp on one bank of the river is inclined at 53(degrees) above the horizontal and is 100m above the level of the river. If the bank on the far side is 15 m below the top of the takeoff ramp, what minimum velocity must he have to reach the opposite bank?
Homework Equations
[tex]\Delta[/tex]y = v0yt - .5gt2
[tex]\Delta[/tex]x = v0xt
R = [tex]\frac{v2sin2\Theta}{g}[/tex]
The Attempt at a Solution
I've made several attempts to solve this during the test, I'm completely stuck though.
With having 2 variables missing I can't solve the conventional way (Solving for t using the y displacement) because I don't know the 'y' component of velocity.
I don't see how it is possible to solving for t in the x dimension because, ini x velocity is unknown and time is unknown.
Using the max range formula wouldn't do me any good either, because there is a displacement in the y dimension. Even if I try to partially solve using the max range formula I fail, I do not know what distance before the cliff to use as range R
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Right now I'm thinking this problem isn't possible to solve, which is most likely not the case considering it was a test problem.
Extremely eager for someone to prove me wrong:
All help appreciated
-Pat