- #1
Lori
✱✱ members reminded to use the homework forum for homework-type questions ✱✱
I want to know if i did this problem correctly!
Problem: A projectile is traveling with velocity vector v = (30.00 m/s)i + (20.0 m/s)j when it experiences an acceleration of vector a = (-10.00 m/s^2)j. What is its velocity after 2.0 s? What is its speed after 2.0 s?
My work:
Vy = V0y - gt = 20 - (-10)2 = 40 m/s
Vx = 30 (constant)
Vector v = sqrt( vy^2 +vx^2) = 50
Angle = atan(vy/vx) = 53.13 degrees
Answer:
Speed is 50 m/s
Velcoity is 50 m/s with angle 53.13 degrees
What's the difference between speed and velocity? They are the same except the velocity has direction right?
Problem: A projectile is traveling with velocity vector v = (30.00 m/s)i + (20.0 m/s)j when it experiences an acceleration of vector a = (-10.00 m/s^2)j. What is its velocity after 2.0 s? What is its speed after 2.0 s?
My work:
Vy = V0y - gt = 20 - (-10)2 = 40 m/s
Vx = 30 (constant)
Vector v = sqrt( vy^2 +vx^2) = 50
Angle = atan(vy/vx) = 53.13 degrees
Answer:
Speed is 50 m/s
Velcoity is 50 m/s with angle 53.13 degrees
What's the difference between speed and velocity? They are the same except the velocity has direction right?