- #1
Warr
- 120
- 0
Ok, in this problem, only the y direction is dealt with
Here is the problem
You are standing on top of a building, 30 m above the ground. You throw a ball (m = 0.15 kg) with an initial velocity or 20 m/s (in the y direction). Air resistance is given as (1/30)*v (yet again only considering the y direction because range is not an issue here).
a) find the maximum height of the ball
b) find the time t when the ball hits the ground 30 m below you
Ok so I set it up like this
mv' = -mg - v(1/30)
v' = -g - v(1/30m)
from here I get kind of confused.
I tried this
v' + v(1/30m) = -g
(e^(t/30m)v)' = -ge^(t/30m)
integrating:
e^(t/30m)v = -30mge^(t/30m) + c
v = -30mg + c/(e^(t/30m))
I'm pretty sure I'm wrong by here. Help would be appreciated.
Here is the problem
You are standing on top of a building, 30 m above the ground. You throw a ball (m = 0.15 kg) with an initial velocity or 20 m/s (in the y direction). Air resistance is given as (1/30)*v (yet again only considering the y direction because range is not an issue here).
a) find the maximum height of the ball
b) find the time t when the ball hits the ground 30 m below you
Ok so I set it up like this
mv' = -mg - v(1/30)
v' = -g - v(1/30m)
from here I get kind of confused.
I tried this
v' + v(1/30m) = -g
(e^(t/30m)v)' = -ge^(t/30m)
integrating:
e^(t/30m)v = -30mge^(t/30m) + c
v = -30mg + c/(e^(t/30m))
I'm pretty sure I'm wrong by here. Help would be appreciated.