Projectile Motion with Quadratic Drag: Solving for Vertical Motion Equation

In summary, the conversation is about solving for an equation of motion y(v) for a baseball thrown up into the air with quadratic drag. The equation d/dt v = -g[1+(v/v_t)^2] is correct and can be rewritten as v/[1+(v/v_t)^2] dv = -g dy. After integrating both sides, the final equation is gy = 1/2 v_t^2 ln(v_t^2+v^2)+C. The speaker initially had some confusion about taking the logarithm of a non-unitless number, but eventually solved the problem and ended up with the final equation y = v_t^2/2g ln((v_t^2+v^2)/v
  • #1
gms7777
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Homework Statement


This is a small part of a problem I'm getting stuck on. I'm going to skip past the beginning steps to a part that I know is correct before I get stuck.
We have a baseball thrown up into the air, with quadratic drag. I'm attempting to solve for an equation of motion y(v).

Homework Equations



The Attempt at a Solution



We end up getting an equation

d/dt v = -g[1+(v/v_t)^2]

(I know that this is correct, the book gives it)

where v_t is the terminal velocity. We can then rewrite d/dt v = v dv/dy.

After separating variables, I get

v/[1+(v/v_t)^2] dv = -g dy

I integrate both sides and get

gy = 1/2 v_t^2 ln(v_t^2+v^2)+C

This is really the part where I'm confused. I thought that we can't take the logarithm of a non-unitless number and v_t^2+v^2 is definitely not unitless.
 
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  • #2
Well, I solved my own problem. I redid the integral and ended up with

y = v_t^2/2g ln((v_t^2+v^2)/v_t^2) + c

Thanks anyway. :)
 

FAQ: Projectile Motion with Quadratic Drag: Solving for Vertical Motion Equation

What is a projectile problem with drag?

A projectile problem with drag is a physics problem that involves calculating the trajectory of an object that is affected by air resistance, or drag. This type of problem is typically solved using equations from projectile motion and incorporating the effects of air resistance.

How is air resistance or drag calculated?

Air resistance or drag is calculated using the equation Fd = 0.5 * ρ * v2 * Cd * A, where Fd is the drag force, ρ is the density of air, v is the velocity of the object, Cd is the drag coefficient, and A is the cross-sectional area of the object.

What factors affect the amount of air resistance or drag on an object?

The amount of air resistance or drag on an object is affected by several factors, including the object's velocity, its size and shape, the density of the air, and the viscosity of the air. Additionally, the presence of any obstacles or turbulence in the air can also affect the amount of drag on an object.

How does air resistance or drag affect the trajectory of a projectile?

Air resistance or drag can significantly alter the trajectory of a projectile by slowing it down and changing its direction. This is because the drag force acts in the opposite direction of the projectile's motion, causing it to lose kinetic energy and change its velocity. This can result in a shorter range and a steeper trajectory compared to a projectile without air resistance.

Are there any real-life applications of projectile problems with drag?

Yes, projectile problems with drag have many real-life applications, such as calculating the trajectory of a rocket or a ball thrown in the air. Understanding the effects of air resistance can also help engineers design more efficient and aerodynamic vehicles and structures.

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