Projectile question - X and Y direction

In summary, the bullet is fired at an angle of 60° with an initial velocity of 200 m/s. Using the equations Vix = Vicosθ and Viy = Visinθ, we can calculate the x and y components of the initial velocity to be 100 m/s and 173.2 m/s, respectively. Assuming the bullet is fired from ground level and into a flat landscape, we can use the equation Y = Viyt - 1/2at^2 to solve for the time the bullet is in the air, which is equal to 35.4 seconds.
  • #1
anthony123456
7
0
A bullet is fired at an angle of 60° with an initial velocity of 200 m/s. How long is the bullet in the air?

Homework Equations



Vix = Vicosθ
Viy = Visinθ

Vfy = Viy + ayΔt
Xf = xi + VixΔt

... Ask for more equations available...

The Attempt at a Solution



Vix = 200cos60° = 100m/s
Viy = 200sin60° = 173.2 m/s

X variables:
xi = 0m
xf = ?
Δt =?
Vix = 100m/s


Y variables:
Yi = ?
Yf = 0m
Δt =?
Viy = 173.2m/s
Vfy = ?
a = -9.8m/sANSWER HAS TO EQUAL 35.4 SECONDS, ACCORDING TO MY PHYSICS TEACHER!
 
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  • #2
Relevant Equation
[itex]Y=(V_{iy})t-\frac{1}{2}at^2[/itex]
 
  • #3
The question is unanswerable, because you are not given knowledge about the initial y-component position of the bullet or the landscape into which the bullet will travel.

But if we assume your teacher meant to describe a world in which bullets are fired from ground level into landscapes that are perfectly flat, we can proceed. If that is the case, Yi = 0. If you need additional help, just ask for it.
 

FAQ: Projectile question - X and Y direction

1. What is a projectile in the X and Y direction?

A projectile in the X and Y direction refers to an object that is launched or thrown and moves in both the horizontal (X) and vertical (Y) directions simultaneously. This type of motion is also known as two-dimensional motion.

2. What is the equation for calculating the X and Y components of a projectile's motion?

The X and Y components of a projectile's motion can be calculated using the following equations:

X-component: Vx = V0 * cosθ

Y-component: Vy = V0 * sinθ - gt

Where Vx and Vy are the velocity in the X and Y directions, V0 is the initial velocity, θ is the launch angle, and g is the acceleration due to gravity (9.8 m/s²).

3. How does the angle of launch affect a projectile's motion in the X and Y direction?

The angle of launch, θ, directly affects the X and Y components of a projectile's motion. The horizontal distance traveled by the projectile is directly proportional to the cosine of the launch angle, meaning that the greater the angle, the farther the projectile will travel in the X direction. The vertical distance is directly proportional to the sine of the launch angle, meaning that the greater the angle, the higher the projectile will go in the Y direction.

4. What is the maximum height a projectile can reach in the X and Y direction?

The maximum height a projectile can reach in the X and Y direction is dependent on the initial velocity, launch angle, and acceleration due to gravity. Using the equation Vy = V0 * sinθ - gt, we can calculate the maximum height by setting Vy to 0 and solving for t, then substituting that value into the equation for the Y-component of velocity.

5. How does air resistance affect a projectile's motion in the X and Y direction?

Air resistance, also known as drag, can have a significant impact on a projectile's motion in the X and Y direction. As a projectile moves through the air, it experiences a force in the opposite direction of its motion, which can decrease its speed and alter its trajectory. This can result in a shorter horizontal distance traveled and a lower maximum height reached compared to a projectile in a vacuum. The effect of air resistance is dependent on factors such as the shape and size of the projectile and the density of the air.

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