Projectile Range Homework | Help Solve Equation

In summary, the problem involves finding the angle (theta) in a projectile system with known velocity, target distance, gravity, and launch height. The equation for this problem is shown in an attached image. The attempt at a solution involved using these values to solve for the angle.
  • #1
rajesh.msen
6
0

Homework Statement


Hi to all guys i am not good in physics and trigonometric I tried to do a projectile system.My launch point is higher than target point.I know the velocity v, target_distance d, gravity g,Launch_height_y y0.I added a image that shows the equation.I tried my own but solved the equation.Please some one help me

d = 30,v = 22, g = 9.8 ,y0 = 2


Homework Equations





The Attempt at a Solution






Homework Equations





The Attempt at a Solution

 

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  • #2
I know the velocity v, target_distance d, gravity g,Launch_height_y y0.I added a image that shows the equation.I tried my own but solved the equation
In this problem, which quantity you want to find out?
 
  • #3
i want to find out the angle(theata)
 

FAQ: Projectile Range Homework | Help Solve Equation

What is a projectile range?

A projectile range is the horizontal distance traveled by an object that is launched into the air at an angle. It is the total distance covered by the object before it returns to its original height.

How do you calculate the projectile range?

The projectile range can be calculated using the equation: R = (v2 * sin2θ)/g, where R is the range, v is the initial velocity, θ is the launch angle, and g is the acceleration due to gravity (9.8 m/s2).

What are the units for projectile range?

The units for projectile range are meters (m) or feet (ft), depending on the unit of measurement used for the other variables in the equation.

Can you provide an example of solving a projectile range equation?

Sure, let's say a ball is thrown with an initial velocity of 20 m/s at an angle of 45 degrees. Using the equation R = (v2 * sin2θ)/g, we get R = (202 * sin2(45))/9.8. Solving this, we get a projectile range of approximately 41 meters.

How does air resistance affect the projectile range?

Air resistance can affect the projectile range by reducing the initial velocity of the object and altering its trajectory. This leads to a shorter range than predicted by the projectile range equation, as it does not take into account the effects of air resistance.

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