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We know that an inhomogeneous Poisson process is a process with a rate function $\lambda(t)$. That is, for any time interval $[t, t+\Delta t]$, $P\left \{ k \;\text{events in}\; [t, t+\Delta t] \right \}=\frac{\text{exp}(-s)s^k}{k!}$, where $s=\int_{t}^{t+\Delta t}\lambda(t)dt$.
And Here is the problem:Assume $s=(s_1,\cdots,s_n)$ is a simulation of an inhomogeneous Poisson process with rate function $\lambda(t)$, $0≤t≤T$. Let $\gamma$ be a mapping from $[0, T]$ to $[0, T]$ which satisfies: 1) $\gamma(0)=0$; 2) $\gamma(T)=T$; 3) $0<\gamma'<\infty$ ($\forall t\in [0,T]$) where $\gamma'$ denotes the derivative of $\gamma(t)$ with respect to $t$. Prove that $\gamma^{-1}(s)=(\gamma^{-1}(s_1),\cdots,\gamma^{-1}(s_n))$ is also an inhomogeneous Poisson process, with rate function $\lambda(\gamma (t))\gamma'(t)$.My question is do we need to use the expression of $\gamma^{-1}(s)$ or we can just use the definition from inhomogeneous Poisson process?
Thanks in advance!
And Here is the problem:Assume $s=(s_1,\cdots,s_n)$ is a simulation of an inhomogeneous Poisson process with rate function $\lambda(t)$, $0≤t≤T$. Let $\gamma$ be a mapping from $[0, T]$ to $[0, T]$ which satisfies: 1) $\gamma(0)=0$; 2) $\gamma(T)=T$; 3) $0<\gamma'<\infty$ ($\forall t\in [0,T]$) where $\gamma'$ denotes the derivative of $\gamma(t)$ with respect to $t$. Prove that $\gamma^{-1}(s)=(\gamma^{-1}(s_1),\cdots,\gamma^{-1}(s_n))$ is also an inhomogeneous Poisson process, with rate function $\lambda(\gamma (t))\gamma'(t)$.My question is do we need to use the expression of $\gamma^{-1}(s)$ or we can just use the definition from inhomogeneous Poisson process?
Thanks in advance!