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MeConfused
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Homework Statement
Problem 1
Assuming that the people in D and C all have KTP (Citizen ID in my country) IDs, let:
D = {x |x is the KTP ID of a student in your Basic Calculus class},
C = {y |y is the KTP ID of the biological father/mother of a student in your Basic Calculus class},
and f : D ->C be the function that relates a student in your Basic Calculus class to his/her
biological father and mother.
1. It is clear that f does not exist. Why?
2. You can fix C such that f exists. Express your fix formally using the set-builder notation,
and then, formally define f!Problem 2
Proof by contradiction that if p^2 is an odd number, then p is an odd number too, profided
p is an element of integer numbers
Homework Equations
The Attempt at a Solution
Problem 1
1. Because a case can occur when both the student's father and mother are in the list as there is no rule that say it can't, if that occur, then f is not a function as it fails the vertical line test
2.D= {x|x is the KTP ID of a student in calculus class}
C= {y|y is the KTP ID of either a student's father or mother}
f(x)= KTP number of a student's father or mother
I've submitted these answers to my lecturer and have been told that both were wrong. Number 2 is wrong my way of fixing it does not uphold the required relationship
Problem 2
I've followed like they did here http://proofsfromthebook.com/2014/09/28/odd-and-square/. I thought it's proof by contraposition and told by my lecturer that it was.