- #1
mcintyre_ie
- 66
- 0
Hi,
I'm having trouble with a proof regarding the rank of the transpose of a matrix. Here's the question:
Let A be an m x n matrix of rank r, which is of course less than or equal to min{m,n}. Prove that (A^t)A has the same rank as A.
Where A^t = the transpose of A.
I can easily prove that the rank of A^t = rank of A, however I'm havin difficulty with this proof.
It's urgently needed for an exam coming up in the next day or two, so I appreciate any help you can give me.
I'm having trouble with a proof regarding the rank of the transpose of a matrix. Here's the question:
Let A be an m x n matrix of rank r, which is of course less than or equal to min{m,n}. Prove that (A^t)A has the same rank as A.
Where A^t = the transpose of A.
I can easily prove that the rank of A^t = rank of A, however I'm havin difficulty with this proof.
It's urgently needed for an exam coming up in the next day or two, so I appreciate any help you can give me.