- #1
Kiwi1
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Suppose [K:F]=n, where K is a root field over F. Prove K is a root field over F of every irreducible polynomial of degree n in F[x] having a root in K.
I don't believe my solution to this problem because I 'prove' the stronger statement: "K is a root field over F for every irreducible polynomial in F[x] having a root in K."
Have I done something wrong?
I have
"Theorem 7: Let K be the root field of some polynomial q(x) over F. For every irreducible polynomial p(x) in F[x], if p(x) has one root in K, then p(x) must have all of its roots in K."
My solution:
K is a root field so there exists a polynomial p(x) such that K is the root field of p(x) over F.
Suppose there is another polynomial b(x) with a root in K and root field \(K_1\). By theorem 7 all of the roots of b(x) are in K. So \(K \supseteq K_1\).
Now \(K_1\) is a root field, what's more it contains a root of p(x) so by Theorem 7 \(K_1\) contains all of the roots of p(x).
Therefore \(K \subseteq K_1\)
and \(K = K_1\)
I don't believe my solution to this problem because I 'prove' the stronger statement: "K is a root field over F for every irreducible polynomial in F[x] having a root in K."
Have I done something wrong?
I have
"Theorem 7: Let K be the root field of some polynomial q(x) over F. For every irreducible polynomial p(x) in F[x], if p(x) has one root in K, then p(x) must have all of its roots in K."
My solution:
K is a root field so there exists a polynomial p(x) such that K is the root field of p(x) over F.
Suppose there is another polynomial b(x) with a root in K and root field \(K_1\). By theorem 7 all of the roots of b(x) are in K. So \(K \supseteq K_1\).
Now \(K_1\) is a root field, what's more it contains a root of p(x) so by Theorem 7 \(K_1\) contains all of the roots of p(x).
Therefore \(K \subseteq K_1\)
and \(K = K_1\)