- #1
smoothman
- 39
- 0
How would you prove the following:
let V be an inner product space. For v,w [itex]\epsilon[/itex] V we have:
|<v,w>| [itex]\leq[/itex] ||v|| ||w||
with equality if and only if v and w are linearly dependent.
-----------------------------------------------------------------
So far I know that the Cauchy-Schwartz inequality says |< v,w>| is less than or equal to ||v||||w|| for any two vectors v and w in an inner product space.
I also realize i have to prove
|< v, w>|< ||v||||w||
that is, that there is a strict inequality, except in the case where one vector is a multiple of the other.
------------------------------------------------------------------
any ideas on the proof for this please
let V be an inner product space. For v,w [itex]\epsilon[/itex] V we have:
|<v,w>| [itex]\leq[/itex] ||v|| ||w||
with equality if and only if v and w are linearly dependent.
-----------------------------------------------------------------
So far I know that the Cauchy-Schwartz inequality says |< v,w>| is less than or equal to ||v||||w|| for any two vectors v and w in an inner product space.
I also realize i have to prove
|< v, w>|< ||v||||w||
that is, that there is a strict inequality, except in the case where one vector is a multiple of the other.
------------------------------------------------------------------
any ideas on the proof for this please