- #36
Deveno
Science Advisor
Gold Member
MHB
- 2,726
- 6
As I see it, you've proved:
$e^{iz} = \cos\theta + i \sin\theta$ for some $\theta \in [0,2\pi)$
I see no problem with assuming $z \in \Bbb R$ but I think you still have to show:
$z - \theta = 2k\pi,\ k \in \Bbb Z$
$e^{iz} = \cos\theta + i \sin\theta$ for some $\theta \in [0,2\pi)$
I see no problem with assuming $z \in \Bbb R$ but I think you still have to show:
$z - \theta = 2k\pi,\ k \in \Bbb Z$