- #1
jacquelinek
- 3
- 0
Prove that:
g is a generator of Fp* if and only if g^(p-1) = 1 (mod p) and gq ≠ 1 (mod p) for all prime divisors q of (p – 1).
I am thinking about applying Fermat's theorem...but don't know how...
Request help, thanks.
g is a generator of Fp* if and only if g^(p-1) = 1 (mod p) and gq ≠ 1 (mod p) for all prime divisors q of (p – 1).
I am thinking about applying Fermat's theorem...but don't know how...
Request help, thanks.