Proof of Integral Relation for Scalar Functions with Gradient

In summary, the conversation discusses proving a mathematical equation involving scalar functions and an elementary region in space. The participants mention using the definition of grad, div, and curl, as well as the integration by parts and differential product rule theorems to help solve the problem.
  • #1
Benny
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Hi, I'm stuck on the following question.

Q. Let f(x,y,z) and g(x,y,z) be C^2 scalar functions. Let D be an elementary region in space and [tex]\partial D[/tex] be the closed surface that bounds D. Prove that:

[tex]
\int\limits_{}^{} {\int\limits_{}^{} {\int\limits_D^{} {\nabla f \cdot \nabla g} } } dV = \int\limits_{}^{} {\int\limits_{\partial D}^{} {f\nabla g \cdot d\mathop S\limits^ \to } } - \int\limits_{}^{} {\int\limits_{}^{} {\int\limits_D^{} {f\nabla ^2 } gdV} }
[/tex]

I've had practice doing some identity problems involving grad, div and curl. In those questions I've just started with the definition and have usually managed to get to the required result. However, I don't know where to start with this one. I can't think of any theorems which I could use to get things going. Can someone please help me get started? Thanks.
 
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  • #2
This is a higher dimensional analog of integration by parts, which is the integral form of the differential product rule. See if a product rule helps you here.
 
  • #3
Thanks for the hint StatusX, I'll see what I can come up with.
 

FAQ: Proof of Integral Relation for Scalar Functions with Gradient

What is the proof of integral relation for scalar functions with gradient?

The proof of integral relation for scalar functions with gradient is a mathematical proof that shows the relationship between a scalar function and its gradient in terms of integration. It states that the integral of a scalar function over a region is equal to the integral of its gradient over the boundary of the region.

Why is the proof of integral relation important?

The proof of integral relation is important because it helps to understand the fundamental concept of integration and its relationship to gradients. It is also a key tool in many areas of mathematics and physics, such as vector calculus and fluid dynamics.

How is the proof of integral relation derived?

The proof of integral relation is derived using the fundamental theorem of calculus, which states that the integral of a function can be calculated by evaluating its antiderivative at the endpoints of the integration interval. By applying this theorem to the integral of a scalar function with its gradient, the proof can be derived.

What are some real-world applications of the proof of integral relation?

The proof of integral relation has many real-world applications, such as in physics for calculating work and energy in a conservative force field, and in engineering for calculating fluid flow and heat transfer. It is also used in economics for calculating consumer and producer surplus.

Are there any limitations to the proof of integral relation?

One limitation of the proof of integral relation is that it only applies to scalar functions with continuous partial derivatives. This means that it may not be applicable to certain types of functions or in cases where the function is not continuous or differentiable. Additionally, the proof may become more complex in higher dimensions and may not always have a closed-form solution.

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