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koab1mjr
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Homework Statement
Let (Tn) be a bounded sequence and let (Sn) be a sequence whose limit = 0. PRove that the limit of (Tn*Sn) = 0. I must complete the proof using only the definition of a limit of a sequence
Homework Equations
Let Sn be a sequence from N->R with a limit of s
For all epsilon > 0 there exists an n > N, such that |Sn - s| < epsion
The suprenum of a sequence is the least upper bound
The Attempt at a Solution
I am used to the numerical proofs showing limits I am not comfortable with manipulating these more abstract ones. I cannot solve for N so I am stuck but here is what I am working off of...
Since Tn is a bounded sequence, by the completeness axiom of R I know that a suprenum exisit and I call it U
Since Sn is a sequence that converges I know for epsilon > 0 there exist an n > N(For s) such that |Sn|< epsilon
I need to show that there is an N for any epsilon that implies |Sn*Tn - 0*U| < epsilon
I was debating proving that the Tn limit is the sup T then provoing the multiplaction of limits rule but that does not sound right there should be a direct method I need some hints on how to start this proof many thanks