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acddklr06
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Hi Everyone!
I decided recently to start reading a book that acts as a transition to upper level mathematics. The last section of the chapter introduces you to the different proof techniques and mathematical facts to produce mathematical proofs. I think I understand everything, but I wanted to make sure by sharing my proof for a problem in the book. If anybody can chime in about if it is right or the like, please do so.
The product of two odd integers is odd.
N/A
Let m and n be two odd integers. We will prove that if m and n are odd integers, then the product of m and n is odd. Since m and n are odd, there exists two integers, i and j, that are an element of Z such that m=2i+1 and n=2j+1. Substituting (2i+1) and (2j+1) into m*n, we produce (2i+1)(2j+1) =>4ij+2j+2i+1 => 2(2ij+j+i)+1, where (2ij+j+1) is an integer. Since (2ij+j+1) is an integer, there exists an integer k that is an element of Z such that (2ij+j+1)=k. By substituting k for (2ij+j+1), we produce 2k+1, which is the definition of an odd number. Therefore, the product of two odd integers is odd.
I decided recently to start reading a book that acts as a transition to upper level mathematics. The last section of the chapter introduces you to the different proof techniques and mathematical facts to produce mathematical proofs. I think I understand everything, but I wanted to make sure by sharing my proof for a problem in the book. If anybody can chime in about if it is right or the like, please do so.
Homework Statement
The product of two odd integers is odd.
Homework Equations
N/A
The Attempt at a Solution
Let m and n be two odd integers. We will prove that if m and n are odd integers, then the product of m and n is odd. Since m and n are odd, there exists two integers, i and j, that are an element of Z such that m=2i+1 and n=2j+1. Substituting (2i+1) and (2j+1) into m*n, we produce (2i+1)(2j+1) =>4ij+2j+2i+1 => 2(2ij+j+i)+1, where (2ij+j+1) is an integer. Since (2ij+j+1) is an integer, there exists an integer k that is an element of Z such that (2ij+j+1)=k. By substituting k for (2ij+j+1), we produce 2k+1, which is the definition of an odd number. Therefore, the product of two odd integers is odd.