- #1
Amad27
- 412
- 1
Homework Statement
Prove that
[tan(a) + 1][cot(a+pi/4) + 1] = 2
Homework Equations
[tan(a) + 1][cot(a+pi/4) + 1] = 2
The Attempt at a Solution
This was very hard, I tried my best at expanding.
[tan(a) + 1][cot(a+pi/4) + 1] = tan(a)cot(a+pi/4) + tan(a) + cot(a+pi/4) + 1
The issue is that there is no cofuntion identity for cot(a + pi/4) so I did
cot(a + pi/4) = cot([a - pi/4] + pi/2]) Let b = a - pi/4 thus,
cot(b + pi/2) = -tan(b) = -tan(a - pi/4)
This doesn't help AT ALL.
Any help?
Thanks