Proof that x^s/s equals 1 if x > 1 where the function is integrated with limits

In summary, the problem is that we need to show that the semicircle part of the contour integral goes to zero. This is done using the residue theorem and the Jordans lemma.
  • #1
jack5322
59
0
can someone prove this for me using a semicircle contour as opposed to a rectangle? I always get nowhere with the semicircle.
 
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  • #2
the limits are from c - infinity*i to c + infinity*i where c is a constant bigger than zero.
 
  • #3
It would help a lot if you would tell us what the problem really is!
 
  • #4
prove:

x^s/s integrated from c-infinity*i to c+infinity*i, where c is any constant bigger than zero, is equal to 1 if x is bigger than 1. The outline of the proof is that we use a semicircle contour enclosing the origin, whose line segment parallel to the imaginary axis is intersecting the real axis at x=c and the semicircle part goes to the left obviously, if it encloses the origin, since c is positive. We then proceed to show that the total contour integral equals 1, and the semi circle part equals zero, giving the desired result. The part i am having difficulty in is proving that the semicircle part goes to zero. any help would be greatly appreciated.
 
  • #5
Should that be "if s is bigger than 1"?
 
  • #6
no, s is the variable we are integrating. The integrand, including the dummy variable, is x^s/sds.
 
  • #7
So, this is an inverse Laplace transform problem. We know that the Laplace transform of the constant function equal to 1 is 1/s, so transforming it back should yield 1. You want to verify this via direct computation.

THe integral is than as you said it is, but with a 1/(2 pi i) factor in front of it. If you close the contour with the semi-circle, then you can directly apply the residue theorem. There is a pole at s = 0, the residue there is 1.
 
  • #8
Yes, but can you show me how the semicircle goes to zero?
 
  • #9
You can write x^s as exp(s t) with t = Log(x) > 0. The proof that the semi-circle goes to zero is practically the same as in the case of the integral of sin(x)/x.
 
  • #10
Oh, it comes from jordans lemma, thank you! I guess i was caught up on this problem because the book problems in analytic number theory by murty doesn't thoroughly explain it, at least to my satisfaction. I think its mistaken, though. If you have it, could you please take a look at it and give me your insight on why I am incorrect?
 

FAQ: Proof that x^s/s equals 1 if x > 1 where the function is integrated with limits

What is the function x^s/s?

The function x^s/s is an integral function that represents the area under the curve of x^s from 0 to a given limit, s. It is commonly used in calculus to find the average value of a function over a given interval.

Why is the proof of x^s/s equaling 1 only valid for x > 1?

The proof for x^s/s equals 1 is based on the geometric interpretation of the integral, where the area under the curve is equal to the base multiplied by the height. When x is greater than 1, the function x^s is always increasing and positive, resulting in a larger area under the curve. This is not always the case when x is less than 1, making the proof invalid.

What are the limits of integration in this proof?

The limits of integration are from 0 to a given limit, s. This means that the function is being integrated over the interval of 0 to s, and the area under the curve between these limits is being calculated.

Can this proof be extended to other functions besides x^s?

Yes, this proof can be extended to other functions as long as they meet certain criteria. The function must be continuous and positive on the interval of integration, and it must also be greater than 1 for the proof to be valid.

How is this proof useful in scientific research?

This proof is useful in scientific research as it provides a way to calculate the average value of a function over a given interval. It is commonly used in physics, engineering, and economics to analyze and model real-world phenomena. It also has applications in probability and statistics, where it is used to calculate the expected value of a random variable.

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