Proper distance, Area and Volume given a Metric

In summary, the conversation discusses finding the proper distance, area, volume, and four-volume using a given metric. The proper distance is found by integrating from 0 to R, the proper area is found by setting r=R and integrating, and the proper volume is found by integrating from 0 to R. The four-volume is found by integrating using a different method. The method used may be a warm-up for more complex work involving the metric.
  • #1
unscientific
1,734
13

Homework Statement


[/B]
(a) Find the proper distance
(b) Find the proper area
(c) Find the proper volume
(d) Find the four-volume

ricci2.png


Homework Equations

The Attempt at a Solution



Part (a)

Letting ##d\theta = dt = d\phi = 0##:

[tex] \Delta s = \int_0^R \left( 1-Ar^2 \right) dr = R \left(1 - \frac{AR}{2} \right) [/tex]

Part (b)

At ##r=R##:

[tex]A = R^2 \int_0^{2\pi} d\phi \int_0^{\pi} sin \theta d\theta [/tex]
[tex]A = 4\pi R^2 [/tex]

Part (c)

[tex]V = \int_0^R r^2 \left( 1 - Ar^2 \right) dr \int_0^{\pi} sin \theta d\theta \int_0 ^{2\pi} d\phi [/tex]
[tex]V = \frac{4}{3} \pi R^3 \left( 1 - \frac{3}{5} AR^2 \right) [/tex]

Part (d)

[tex]V_4 = c\int_0^R r^2 \left( 1 - Ar^2\right)^2 dr \int_0^T dt \int_0^{\pi} sin \theta d\theta \int_0^{2\pi} d\phi [/tex]

[tex]V_4 = \frac{4}{3} \pi R^3 \cdot cT \cdot \left( 1 - \frac{6}{5}AR^2 + \frac{3}{7}A^2R^4 \right) [/tex]Is this the correct method? This question seems a little too straightforward..
 
Physics news on Phys.org
  • #2
I would guess that, if you look forward in your text, you will find this metric gets a lot of work. For example, you may be doing some interesting work studying the place where r^2 = 1/A.

So quite likely this is just a warm-up getting some interesting features of the metric.
 

FAQ: Proper distance, Area and Volume given a Metric

What is proper distance in terms of a metric?

Proper distance is a metric measurement that represents the shortest distance between two points in a given space. It takes into account the curvature of the space, and is often used in cosmology to describe the distance between galaxies.

How is proper distance different from Euclidean distance?

Euclidean distance is the straight-line distance between two points in flat, two-dimensional space. Proper distance, on the other hand, takes into account the curvature of space and can be measured in any number of dimensions. It is a more generalized concept that is used in non-Euclidean geometries.

How is proper distance calculated?

The calculation of proper distance depends on the specific metric being used. In general, it involves integrating the metric function over the path between the two points. In simpler cases, such as in flat space, the calculation can be reduced to a simple formula using the Pythagorean theorem.

What is the relationship between proper distance and area?

Proper distance is related to area in that it is a measure of the size of a given space. In some cases, the proper distance between two points can be used to calculate the area of a surface that connects those points. This is often seen in calculations of the surface area of a sphere or other curved object.

How does proper distance relate to volume?

Proper distance is also related to volume, as it is a measure of the size of a space. In some cases, the proper distance between two points can be used to calculate the volume of a region that contains those points. This is often seen in calculations of the volume of a sphere or other curved object.

Back
Top