Proportionality of frictional force

In summary, the problem involves a mass-spring system subject to a frictional force that is proportional and opposite to the velocity. The amplitude of the oscillation decreases over time and after 8.8 seconds, it is half of the original amplitude. The value of the constant of proportionality for the frictional force is needed. The equation for frictional force is Ff=-vμ, where μ is the constant of proportionality. The problem also requires constructing a new equation for the frictional force based on the given information. A free body diagram may be helpful in solving this problem.
  • #1
Dennydont
45
0

Homework Statement


A mass-spring system consisting of a mass of 2.9 kg attached to a spring is subject to a frictional force which is both proportional and opposite to the velocity. The mass is displaced from rest and oscillates back and forth with an ever decreasing amplitude. It is found that after 8.8 seconds the amplitude is half what it was originally. What is the value of the constant of proportionality for the frictional force?

I don't even know where to begin with this! What equations are relevant?! All I know is that the final answer should have units of kg/s or g/s.

Homework Equations

The Attempt at a Solution

 
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  • #2
I don't even know where to begin with this!
... yes you do!
How would you normally begin a problem with a mass and more than one force?
Note: you can start a problem without knowing how to finish it.
 
  • #3
Simon Bridge said:
... yes you do!
How would you normally begin a problem with a mass and more than one force?
Note: you can start a problem without knowing how to finish it.
Well there is the equation for frictional force: Ff=μFn
 
  • #4
Thats the usual relation, it says the amount of friction is proportional to the amount of normal force, but the problem statement gives you a different one for this situation. Use that instead. What does the description say the friction is proportional to?
 
  • #5
Simon Bridge said:
Thats the usual relation, it says the amount of friction is proportional to the amount of normal force, but the problem statement gives you a different one for this situation. Use that instead. What does the description say the friction is proportional to?
To the velocity, but it is also opposite to the velocity?
 
  • #6
Well done, so how do you write that down as maths?
 
  • #7
Simon Bridge said:
Well done, so how do you write that down as maths?
Good question... I don't know. The drag force equation?
 
  • #8
Dont try to think of specific equations just yet. You are constructing a new equation... it may be one you have not seen before or it may be that, once you write it down, you'll recognize it. Just think of the maths as a language.

You can write out the maths for "the friction is proportional to the normal force" ok.
There is nothing here you have not done before.
 
  • #9
Simon Bridge said:
Well done, so how do you write that down as maths?

So would we say that Ff=-vμ ?? To say that the frictional force is proportional and opposite to the velocity multiplied by a constant?
 
  • #10
Sam Fielder said:
So would we say that Ff=-vμ ?? To say that the frictional force is proportional and opposite to the velocity multiplied by a constant?
Please don't answer questions that were directed to the original poster of the thread. You could have asked that via a private conversation with Simon.
 
  • #11
Dennydont,

A more fundamental question: Have you drawn a free body diagram yet, or do you feel like you have advanced beyond the point where you need to use free body diagrams?

Chet
 

FAQ: Proportionality of frictional force

1. What is the relationship between frictional force and the normal force?

The frictional force is directly proportional to the normal force, meaning that as the normal force increases, the frictional force also increases. This can be expressed by the equation Ff = μN, where Ff is the frictional force, μ is the coefficient of friction, and N is the normal force.

2. How does the coefficient of friction affect the frictional force?

The coefficient of friction is a measure of how rough or smooth two surfaces are in contact. A higher coefficient of friction means that the surfaces are rougher, resulting in a stronger frictional force. Conversely, a lower coefficient of friction means that the surfaces are smoother, resulting in a weaker frictional force.

3. What is the difference between static and kinetic friction?

Static friction refers to the force that keeps two surfaces from moving when they are in contact and at rest. Kinetic friction, on the other hand, refers to the force that opposes the motion of two surfaces that are already in motion. The coefficient of static friction is typically higher than the coefficient of kinetic friction.

4. How does surface area affect frictional force?

The surface area in contact between two surfaces does not affect the frictional force. The coefficient of friction remains the same regardless of the surface area. However, a larger surface area can distribute the force of friction over a larger area, resulting in a decrease in pressure and potential damage to the surfaces.

5. What are some factors that can affect the proportionality of frictional force?

Aside from the normal force and coefficient of friction, other factors that can affect the proportionality of frictional force include the nature and condition of the surfaces in contact, the presence of lubricants, temperature, and the relative speed between the surfaces. Additionally, external forces such as air resistance or electrostatic forces may also impact the frictional force.

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