Proton and neutron configurations (shell model)

In summary: This is reflected in the configurations you determined for the first and second excited states. In summary, the neutron configurations for the first and second excited states of _{20}^{41}Ca, with spin-parities of 3/2^{-} and 3/2^{+} respectively, are (1s_{\frac{1}{2}})^{2}(1p_{\frac{3}{2}})^{4}(1p_{\frac{1}{2}})^{2}(1d_{\frac{5}{2}})^{6}(2s_{\frac{1}{2}})^{2}(1d_{\frac{3}{2}})^{4}(2p_{\
  • #1
SUDOnym
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1
Question is:

Determine the neutron and proton configurations of the first and second excited states of:

[tex]_{20}^{41}Ca[/tex]

which have spin-parities of [tex]3/2^{-}[/tex] and [tex]3/2^{+}[/tex] respectively.My attempt at solution:

(I haven't encountered a problem quite of this type before so am a little unsure as to how to go about it...)

But my reasoning was that the proton states would stay the same as if in ground state as there are no unpaired protons, ie.:

protons:
[tex](1s_{\frac{1}{2}})^{2}(1p_{\frac{3}{2}})^{4}(1p_{\frac{1}{2}})^{2}(1d_{\frac{5}{2}})^{6}(2s_{\frac{1}{2}})^{2}(1d_{\frac{3}{2}})^{4}[/tex]

so the difference would lie with the neutrons, first off to say neutron ground state config is:

[tex](1s_{\frac{1}{2}})^{2}(1p_{\frac{3}{2}})^{4}(1p_{\frac{1}{2}})^{2}(1d_{\frac{5}{2}})^{6}(2s_{\frac{1}{2}})^{2}(1d_{\frac{3}{2}})^{4}(1f_{\frac{7}{2}})^{1}[/tex]

and since the first excited state is [tex]3/2^{-}[/tex] I made a guess this means that is only the outer most neutron that jumps up to the nearest level with this spin-parity:

implies first excited state neutron configuration is:

[tex](1s_{\frac{1}{2}})^{2}(1p_{\frac{3}{2}})^{4}(1p_{\frac{1}{2}})^{2}(1d_{\frac{5}{2}})^{6}(2s_{\frac{1}{2}})^{2}(1d_{\frac{3}{2}})^{4}(2p_{\frac{3}{2}})^{1}[/tex]

and the second excited state configuration for neutrons with spin parity given by:
[tex]3/2^{+}[/tex]
is

[tex](1s_{\frac{1}{2}})^{2}(1p_{\frac{3}{2}})^{4}(1p_{\frac{1}{2}})^{2}(1d_{\frac{5}{2}})^{6}(2s_{\frac{1}{2}})^{2}(1d_{\frac{3}{2}})^{4}(2d_{\frac{3}{2}})^{1}[/tex]

So is this the correct method/reasoning I used? if not what is the correct approach to take?
 
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  • #2
Yes, this is the correct method and reasoning you used. The way to approach this type of problem is to look at the ground state configuration and determine which particle in the ground state would have to be excited to a higher energy level with the given spin-parity in order to reach the first and second excited states. In this case, the outermost neutron was needed to be excited to the next higher energy level with the given spin-parity in order to reach the first and second excited states.
 

FAQ: Proton and neutron configurations (shell model)

1. What is the shell model of a proton and neutron configuration?

The shell model is a theoretical framework used to describe the arrangement of protons and neutrons in the nucleus of an atom. It is based on the idea that these particles occupy discrete energy levels or "shells" within the nucleus, similar to how electrons occupy energy levels around the nucleus in the atomic shell model.

2. How does the shell model explain the stability of atoms?

The shell model explains the stability of atoms by showing that when the number of protons and neutrons in a nucleus follows certain patterns, the nucleus becomes more stable. This is because these numbers correspond to completely filled or half-filled shells, which are more stable configurations due to the nuclear forces between particles.

3. What is the difference between the shell model for protons and neutrons?

The shell model for protons and neutrons is the same conceptually, as they both occupy the same types of energy levels within the nucleus. However, the specific energy levels and number of particles in each level can differ between protons and neutrons, as they have different electric charges and therefore experience different forces within the nucleus.

4. How does the shell model explain the properties of isotopes?

The shell model explains the properties of isotopes by showing how the number of protons and neutrons in a nucleus can affect its stability and other properties. For example, isotopes with more neutrons may have a higher energy level or a different number of filled shells, which can impact their stability and reactivity.

5. What are some limitations of the shell model?

The shell model has some limitations, such as not being able to accurately predict the exact position of individual protons and neutrons within the nucleus. It also does not take into account the effects of nuclear forces beyond the nearest neighbors, which can affect the stability of some nuclei. Additionally, the shell model does not explain the behavior of unstable or radioactive nuclei, which require more complex models to describe.

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