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physicsstar26
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Homework Statement
A proton (q=+e, m= 1.67*10^-27 kg) traveling at 300 m/s enters a uniform electric region opposite to the field direction.
a.) find the change in the energy of the proton as it moves 2 m across a potential difference of 100kV in this field. Express answer in eV.
b) find the final speed of the proton in km/s
Homework Equations
a) W=q*V
V= k*q/r I'm confused as to how to approach this problem.
b) once you know V or the above answer do you just plug it into V= (1/2) mv^2/q?
thanks