Prove: a((bc)'d+b)+a'b=(a+b)(b+d)

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In summary, to prove that the left side of the equation equals the right, we can use the distribution and complementary laws to manipulate the left side into a minimal form. This can be achieved by using the redundancy law to simplify and get rid of duplicate terms, and then using the distributive law to factor the expression into (a + b)(b + d).
  • #1
Gee Wiz
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Homework Statement


Prove that the left equals the right.

a((bc)'d+b)+a'b=(a+b)(b+d)



The Attempt at a Solution



ab'd+adc'+ab+a'b distribution
ab'd+adc'+b complementary
I don't know what to do next, or what i should look for to give me a clue as to how to progress.
 
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  • #2
Gee Wiz said:

Homework Statement


Prove that the left equals the right.

a((bc)'d+b)+a'b=(a+b)(b+d)



The Attempt at a Solution



ab'd+adc'+ab+a'b distribution
ab'd+adc'+b complementary
I don't know what to do next, or what i should look for to give me a clue as to how to progress.
A Karnaugh map (K-map) will prove useful.

(By the way, you can reduce both sides of the equation, not just the left side. :wink:)
 
  • #3
we aren't supposed to use the karnaugh map yet, and they only want us to manipulate the left side.
 
  • #4
Gee Wiz said:
we aren't supposed to use the karnaugh map yet, and they only want us to manipulate the left side.

There are a couple of uses of the redundancy law that you can use.

x + x'y = x + y

After that, you can use it again in a different way,

x + xy = x

And you'll reach the minimal solution.

But since the right hand side of the equation is not at its minimal form, you'll have to actually go backwards after that to get the (a+b)(b+d). That is, if you are not allowed to simplify the right hand side.
 
  • #5
So, I would basically want the minimal on the left (before going a little backwards) to be ab+ad+b+ad?
 
  • #6
Gee Wiz said:
So, I would basically want the minimal on the left (before going a little backwards) to be ab+ad+b+ad?
It's even simpler than that! :smile:

Notice that you have "ad" terms in there twice. You can just get rid of one of them (x + x → x). :wink: (But don't get rid of both them, of course).

And then there's still more you can do. There's a "b" all by itself, and then there's another term with "b" in it. Use the redundancy rule,
x + xy → x.
 
  • #7
Got it! Thank you very much.
 
  • #8
Gee Wiz said:
So, I would basically want the minimal on the left (before going a little backwards) to be ab+ad+b+ad?
Oh, wait. Yes, since you're going backward, you'll eventually want to get it into a form that you can factor into (a + b)(b + d) such as, ab + ad + bb + bd.

The point of my last post is that ab+ad+b+ad is still not minimal. That's all I meant.
 

FAQ: Prove: a((bc)'d+b)+a'b=(a+b)(b+d)

What does "Prove: a((bc)'d+b)+a'b=(a+b)(b+d)" mean?

This statement is an algebraic equation that is asking for a proof to show that the left side of the equation is equal to the right side.

How do you solve this equation?

To solve this equation, you can use algebraic properties and manipulation to simplify each side and show that they are equal to each other. This may involve factoring, distributing, or combining like terms.

Can you give an example of how to prove this equation?

Yes, for example, you could start by distributing the a in the first term on the left side of the equation. Then, you could use the distributive property again to expand the (bc)'d term. From there, you can continue manipulating the equation using algebraic properties until you reach the same result on both sides.

Why is it important to prove equations like this?

Proving equations like this is important because it allows us to verify the validity of mathematical statements and ensure that they are always true. It also helps us understand the underlying principles and concepts behind the equation.

Are there any tips for proving this equation?

Yes, one tip is to start by simplifying one side of the equation before trying to make them equal. This can make the process easier and less overwhelming. It is also helpful to use algebraic properties and techniques that you are familiar with to manipulate and simplify the equation.

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