- #1
amits
- 12
- 0
All numbers are equal :D
heres the latest proof and it doesn't involve 0 anywhere. no term like (a-b) is involved unlike other similar proofs
-ab = -ab
=> a^2 - a^2 - ab = b^2 - b^2 - ab
=> a^2 - a(a+b) = b^2 - b(a+b)
=> a^2 - a(a+b) + (a+b)^2/4 = b^2 - b(a+b) + (a+b)^2/4
as (x-y)^2 = x^2 - 2xy + y^2,
[a - (a+b)/2]^2 = [b - (a+b)/2]^2
taking square roots,
a - (a+b)/2 = b - (a+b)/2
a = b
hence proved :D
now with all numbers having been proved equal without involving "0" anywhere, what's the need to study anything :D
just noticed, this is my 1st post here after 7 years
heres the latest proof and it doesn't involve 0 anywhere. no term like (a-b) is involved unlike other similar proofs
-ab = -ab
=> a^2 - a^2 - ab = b^2 - b^2 - ab
=> a^2 - a(a+b) = b^2 - b(a+b)
=> a^2 - a(a+b) + (a+b)^2/4 = b^2 - b(a+b) + (a+b)^2/4
as (x-y)^2 = x^2 - 2xy + y^2,
[a - (a+b)/2]^2 = [b - (a+b)/2]^2
taking square roots,
a - (a+b)/2 = b - (a+b)/2
a = b
hence proved :D
now with all numbers having been proved equal without involving "0" anywhere, what's the need to study anything :D
just noticed, this is my 1st post here after 7 years