- #1
chikou24i
- 45
- 0
How to prove that e(the charge of proton)=1.6E-19 Mev.fm
vanhees71 said:In SI units you have
[itex]\alpha=\frac{e^2}{4 \pi \epsilon_0 \hbar c} \simeq 1/137 [/itex],which is dimensionless.
Vanadium 50 said:Do you two think this is helping the OP?
chikou24i said:ChrisVer I asked a question for you to help me or to correct me if I was wrong,
The charge of a proton is 1.6 x 10-19 coulombs, which is the fundamental unit of electric charge.
The charge of a proton can be measured using a device called an electrometer, which can detect and measure the amount of electric charge present.
The charge of a proton is significant because it is the basis for understanding the behavior of atoms and molecules, as well as the forces between particles in the atomic nucleus.
"MeV" stands for megaelectronvolts, which is a unit of energy commonly used in particle physics to measure the mass and energy of subatomic particles.
The charge of a proton was first determined by physicist Robert Millikan in 1910 through his famous oil drop experiment, which involved balancing the electric forces acting on tiny droplets of oil suspended in an electric field.