- #36
mathwonk
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if you integrate the form dlog(z) = dz/z around the upper half of the unit circle, and get ipi, it seems to me you have proved that e^(ipi) = -1.
i.e. here e^z is defined as the inverse of the integral of dz/z.
i.e. here e^z is defined as the inverse of the integral of dz/z.