- #1
pcming
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I can't find out how to prove this question. Can anyone help?
Let A be an n x m matrix of rank m, n>m. Prove that (A^t)A has the same rank m as A.
Where A^t = the transpose of A.
I seen someone else have asked the question before and had got the answer. However I can't understand it. Hope someone can give me a more detail suggestion. Thanks!
Let A be an n x m matrix of rank m, n>m. Prove that (A^t)A has the same rank m as A.
Where A^t = the transpose of A.
I seen someone else have asked the question before and had got the answer. However I can't understand it. Hope someone can give me a more detail suggestion. Thanks!