- #1
subhradeep mahata
- 120
- 13
Homework Statement
Consider the two homothetic non congruent triangles, with their corresponding sides parallel to each other.
Prove that extended CE, extended DA and extended BF are concurrent.
Homework Equations
The Attempt at a Solution
I can easily solve this using Desargues' theorem. The three points of intersection of corresponding sides are lying on a line, namely the line at infinity. Therefore the three lines connecting corresponding vertices meet in a point. But the task is to prove it using Ceva's theorem, if possible.
I thought of extending CE, DA and BF to touch the opposite sides, but got no clue. Please help me out.