Prove Integer Solution for $x_1^3+x_2^3+x_3^3+x_4^3+x_5^3=k$

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In summary, to prove the existence of integer solutions for the equation $x_1^3+x_2^3+x_3^3+x_4^3+x_5^3=k$, we can use the concept of modular arithmetic and consider all possible remainders when each integer is divided by 9. This allows us to manipulate the equation and show that for any integer $k$, there exists a set of 5 integers that satisfy it. The number 9 is significant in this proof because of its properties in modular arithmetic. Other methods for proving the existence of integer solutions include using complex numbers and perfect cubes, but the most commonly used and efficient approach is through modular arithmetic. This equation can have multiple sets of integer solutions for a
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anemone
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Prove that the equation $x_1^3+x_2^3+x_3^3+x_4^3+x_5^3=k$ has an integer solution for any integer $k$.
 
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Hint:

Note that $k=6n$ can be represented as a sum of four cubes.
 
  • #3
The hint follows from:
\[
(x+1)^3 + (x-1)^3 + (-x)^3 + (-x)^3 = 6x.
\]
Moroever, we have that under $\pmod 6$,
$(\pm 1)^3 \equiv \pm1$, $(\pm 2)^3 \equiv \pm 2$,
$3^3 \equiv 3$. We can choose any of the two of the cubes to form
$6x + k$ where $k = 1..5$.
 
  • #4
magneto said:
The hint follows from:
\[
(x+1)^3 + (x-1)^3 + (-x)^3 + (-x)^3 = 6x.
\]
Moroever, we have that under $\pmod 6$,
$(\pm 1)^3 \equiv \pm1$, $(\pm 2)^3 \equiv \pm 2$,
$3^3 \equiv 3$. We can choose any of the two of the cubes to form
$6x + k$ where $k = 1..5$.

You're right magneto, well done and thanks for participating!:)
 
  • #5


I would approach this problem by first acknowledging that this is a well-known mathematical problem known as the "sum of five cubes." It has been extensively studied by mathematicians over the years, and various proofs have been proposed to show that it has integer solutions for all values of $k$.

One approach to proving the existence of integer solutions for this equation is through the use of modular arithmetic. By considering the equation modulo different numbers, we can show that there are certain patterns and constraints that the solutions must follow. This can help us narrow down the possible values for $x_1, x_2, x_3, x_4,$ and $x_5$ and eventually find an integer solution for any given $k$.

Another approach is through the use of Diophantine equations, which are equations that involve only integer solutions. By transforming the given equation into a Diophantine equation and using techniques such as descent, we can show that there are integer solutions for any value of $k$.

Additionally, there are other methods such as using identities and properties of cubic equations that can help in proving the existence of integer solutions for this equation.

In conclusion, as a scientist, I can confidently say that the equation $x_1^3+x_2^3+x_3^3+x_4^3+x_5^3=k$ has an integer solution for any integer $k$, as it has been proven and studied extensively by mathematicians using various techniques and methods.
 

FAQ: Prove Integer Solution for $x_1^3+x_2^3+x_3^3+x_4^3+x_5^3=k$

How can you prove that there exists an integer solution for the equation $x_1^3+x_2^3+x_3^3+x_4^3+x_5^3=k$?

To prove that there exists an integer solution for this equation, we can use the concept of modular arithmetic. We can show that for any integer $k$, there exists a set of 5 integers $(x_1, x_2, x_3, x_4, x_5)$ that satisfy the equation by considering all possible remainders when each of the integers is divided by 9. We can then use the properties of modular arithmetic to manipulate the equation and show that it is always possible to find a set of integers that satisfy it.

Can you provide an example of an integer solution for the equation $x_1^3+x_2^3+x_3^3+x_4^3+x_5^3=k$?

Yes, an example of an integer solution for this equation is $(x_1, x_2, x_3, x_4, x_5) = (1, 2, 3, 4, 5)$ for $k = 225$. This set of integers satisfies the equation $1^3+2^3+3^3+4^3+5^3=225$.

What is the significance of the number 9 in proving the existence of integer solutions for the equation $x_1^3+x_2^3+x_3^3+x_4^3+x_5^3=k$?

The number 9 is significant because it is the base of the decimal system, and thus has special properties in modular arithmetic. In particular, when we take the remainder of a number divided by 9, we are essentially looking at the digit sum of that number. This allows us to manipulate the equation in a way that helps us find integer solutions.

Are there any other methods for proving the existence of integer solutions for the equation $x_1^3+x_2^3+x_3^3+x_4^3+x_5^3=k$?

Yes, there are other methods such as using the properties of complex numbers or the properties of perfect cubes. However, the method involving modular arithmetic is the most commonly used and efficient approach.

Can this equation have more than one set of integer solutions?

Yes, this equation can have multiple sets of integer solutions for a given value of $k$. For example, for $k=225$, in addition to the solution (1, 2, 3, 4, 5), there is also the solution (6, 6, 6, 6, 0) and many others. This can be shown using the properties of modular arithmetic and the fact that the equation has infinitely many solutions for any integer $k$.

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