- #1
beecher
- 15
- 0
Homework Statement
Using the Lorentz transformation, prove that s2 = s'2
Homework Equations
s2 = x2 - (c2t2)
x' = gamma * (x-Beta*ct)
t' = gamma * (t - Beta*x/c)
The Attempt at a Solution
s2 = x2 - (c2t2)
Therefore
s'2= x'2 - (c2t'2)
and x' = gamma * (x-Beta*ct)
So x'2 = [gamma * (x-Beta*ct)]2
Using FOIL x'2 = gamma2 (x2 - 2xBeta*ct + Beta2*c2t2)
and t' = gamma * (t - Beta*x/c)
So t'2 = [gamma * (t - Beta*x/c)]2
Using FOIL t'2 = gamma2 (t2 - 2Beta*tx/c + Beta2*x2/c2)
combining
s'2 = gamma2 [x2 - 2Beta*cxt + Beta2*c2t2 - c2t2 + 2Beta*cxt - Beta2*x2
Cancel like terms
s'2 = gamma2 [x2 + Beta2*c2t2 - c2t2 - Beta2*x2
This is where I get stuck and can't tell how to progress and make it equal to the original s2 = x2 - (c2t2).
Any insight would be greatly appreciated.
Thanks!