Prove Summation Property: \displaystyle\sum\limits_{i=1}^n aij

In summary, the summation notation satisfies the property that \sum_{i=1}^n\bigg(\sum_{j=1}^m a_{ij}\bigg) = \sum_{j=1}^m\bigg(\sum_{i=1}^n a_{ij}\bigg).
  • #1
-Dragoon-
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Homework Statement


Show that the summation notation satisfies the following property:
[itex]\displaystyle\sum\limits_{i=1}^n(\displaystyle\sum\limits_{j=1}^m aij) = \displaystyle\sum\limits_{j=1}^m(\displaystyle\sum\limits_{i=1}^n aij) [/itex]

Homework Equations


N/A


The Attempt at a Solution


[itex]\displaystyle\sum\limits_{i=1}^n(\displaystyle\sum\limits_{j=1}^m aij) = \displaystyle\sum\limits_{i=1}^n ai_{1} + \displaystyle\sum\limits_{i=1}^n ai_{2} + ... +\displaystyle\sum\limits_{i=1}^n ai_{n} = \displaystyle\sum\limits_{j=1}^m(\displaystyle\sum\limits_{i=1}^n aij) [/itex]

Have I proven this sufficiently or have I skipped a step? If I skipped a step, which one was it? Thanks in advance.
 
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  • #2

Homework Statement


Show that the summation notation satisfies the following property: [tex]\sum_{i=1}^n\bigg(\sum_{j=1}^m a_{ij}\bigg) = \sum_{j=1}^m\bigg(\sum_{i=1}^n a_{ij}\bigg) [/tex]

Homework Equations


N/A

The Attempt at a Solution


[tex]\sum_{i=1}^n\bigg(\sum_{j=1}^m a_{ij}\bigg) = \sum_{i=1}^n a_{i1} + \sum\limits_{i=1}^n a_{i2} + \cdots +\sum_{i=1}^n a_{im} = \sum_{j=1}^m\bigg(\sum_{i=1}^n a_{ij}\bigg) [/tex]
I would at least have written out the step [tex]\sum_{i=1}^n(a_{i1}+\cdots+a_{im})=\sum_{i=1}^n a_{i1} + \sum\limits_{i=1}^n a_{i2} + \cdots +\sum_{i=1}^n a_{im}.[/tex] If you want to do these things rigorously, you need to avoid the ... notation and use induction.

If you use tex tags instead of itex, you don't need to type "displaystyle" all the time. (Use tex tags only when you want the math to appear on a separate line). Hit the quote button to see how I prefer to type the math above.
 
  • #3
Fredrik said:
I would at least have written out the step [tex]\sum_{i=1}^n(a_{i1}+\cdots+a_{im})=\sum_{i=1}^n a_{i1} + \sum\limits_{i=1}^n a_{i2} + \cdots +\sum_{i=1}^n a_{im}.[/tex] If you want to do these things rigorously, you need to avoid the ... notation and use induction.

If you use tex tags instead of itex, you don't need to type "displaystyle" all the time. (Use tex tags only when you want the math to appear on a separate line). Hit the quote button to see how I prefer to type the math above.
Thank you for the help and the tex tips, Fredrik.
 

FAQ: Prove Summation Property: \displaystyle\sum\limits_{i=1}^n aij

What is the summation property?

The summation property states that the sum of a sequence of numbers can be written as a summation expression using the sigma notation, where the lower and upper limits indicate the starting and ending values of the sequence, and the summand is the function or expression to be summed.

How do you prove the summation property?

The summation property can be proven using mathematical induction, where we first show that the property holds for the base case (n=1), and then assume it holds for some arbitrary case (n=k) and use this assumption to prove that it also holds for the next case (n=k+1).

What is the purpose of the summation property?

The summation property is useful in simplifying and expressing large sums in a compact and efficient way. It also allows us to easily manipulate and perform operations on sums, making it a valuable tool in various mathematical and scientific fields.

Can the summation property be applied to any type of sequence?

Yes, the summation property can be applied to any type of sequence, including arithmetic, geometric, and even infinite series. It is a general property that holds for any type of sequence where the terms can be summed.

Are there any limitations or restrictions to using the summation property?

The summation property can only be used for finite sums, meaning that the upper limit of the summation must be a finite number. It also cannot be used for sums with non-constant intervals, as the upper and lower limits must have a constant difference of 1.

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