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Robb said:Homework Statement
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Homework Equations
The Attempt at a Solution
This is where I'm at and I'm not sure what my next step is. Any help would be much appreciated!
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Robb said:This is where I'm not sure. I tried setting min f = (-b^2+ac)/a and solving for x but I'm not sure if that tells me anything and it doesn't relate to the hypothesis. I guess I'm unsure of how to use the hypothesis.
Robb said:Does it have to do with divisibility of a, which must be greater that zero?
Robb said:for all x in R?
Robb said:(a) must be greater than zero but that's a given
Robb said:How does b^2-ac =< 0 tell us that f(x) >= 0?
The statement means that the function f(x) always has a non-negative value for any input value x from the set of real numbers.
b^2-ac is the discriminant of a quadratic equation, which determines the nature of the roots of the equation. In this case, if b^2-ac is less than or equal to zero, the quadratic equation has either two real roots or no real roots, which is necessary for f(x) to be non-negative for all x in R.
To prove that f(x)>=0 for all x in R, we need to show that the discriminant b^2-ac is less than or equal to zero for any real values of a, b, and c in the quadratic equation. This can be done by using the quadratic formula or by completing the square.
Yes, there are other methods to prove that f(x)>=0 for all x in R. For example, we can use the properties of a quadratic function, such as its vertex, to show that the function always has a non-negative value for any input x in the set of real numbers.
The practical application of this proof is that it ensures the reliability and validity of the quadratic function in various mathematical and scientific applications. It also helps in solving optimization problems and in determining the nature of solutions to real-world problems represented by quadratic equations.