Prove this inequality using induction

  • #1
sdfsfasdfasf
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Homework Statement
Given n positive numbers x1, x2, . . . , xn such that x1 + x2 + · · · + xn <= 1/3, prove by
induction that
(1 − x1)(1 − x2) × · · · × (1 − xn) >= 2/3
Relevant Equations
Principle of Induction, proof by induction, base case, inductive step
1728314044959.png



Been stuck on this one for a while now.

Base case is easy, n=1, we have x <=1/3, so trivially 1-x>= 2/3 and we are done.

The issue is with the inductive step, I don't know how to use the hint, infact I am struggling to understand what is meant by the hint.

Any help (or a full solution) would be greatly appreciated.
 
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  • #2
sdfsfasdfasf said:
The issue is with the inductive step, I don't know how to use the hint, infact I am struggling to understand what is meant by the hint.
The hint means that when you have ##n + 1## numbers, you combine the last two numbers by adding them, and then you only have ##n## numbers.
 
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  • #3
To make that a little more explicit: Consider ##x_1 + x_2 = y \leq 1/3##. Then by the ##n=1## case, ##(1-y) \geq 2/3##. Therefore ##(1-x_1)(1-x_2) = 1 - y + x_1 x_2 \geq 1-y \geq 2/3##, which proves the relation for ##n=2##. Now generalize this to an induction step.
 
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FAQ: Prove this inequality using induction

What is mathematical induction?

Mathematical induction is a proof technique used to establish the truth of an infinite sequence of statements. It involves two main steps: the base case, where the statement is shown to be true for the initial value (usually n=1), and the inductive step, where one assumes the statement is true for n=k and then proves it for n=k+1.

How do I set up the base case for an inequality proof using induction?

To set up the base case, you need to verify that the inequality holds true for the smallest integer in your domain, typically n=1. You substitute this value into the inequality and show that the left-hand side is less than or equal to the right-hand side.

What is the inductive hypothesis in an inequality proof?

The inductive hypothesis is the assumption that the inequality holds true for a specific integer n=k. You assume that the statement is valid for this particular value before proceeding to prove that it must also be true for n=k+1.

What should I do in the inductive step for an inequality proof?

In the inductive step, you take the assumption from the inductive hypothesis and use it to show that the inequality also holds for n=k+1. This often involves manipulating the algebraic expressions and applying the inductive hypothesis to reach the desired conclusion.

What if the inequality does not hold for the base case?

If the inequality does not hold for the base case, then the proof by induction fails, and you cannot conclude that the inequality is true for all integers in the specified range. You may need to re-evaluate the inequality, check for any errors, or adjust the starting point of your induction.

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