Prove:β (heat pump) is always less or equal to β(Carnot HP)

In summary, the conversation revolves around understanding the coefficient of performance for heat pumps and refrigerators, and how it relates to the Carnot theory. The process involves using integrals and a temperature vs. entropy plot for a heat engine cycle, as well as the first and second laws of thermodynamics. The goal is to prove that the coefficient of performance for a Carnot cycle is the highest possible, leading to the rule that ##\beta \le \beta(\mathrm{Carnot})## for heat pumps and refrigerators.
  • #1
mek09e
1
0
Hello All!

My professor in thermodynamics showed us the proof of the Carnot theory using integrals and a temp vs. entropy plot for a heat engine cycle. We haven't actually learned about entropy yet, so can someone help me understand how this translates into the coefficient of performance β for a heat pump? We were given the rule that β≤β(Carnot) for heat pumps and refrigerators, but I can't prove this is true on my own. Any explanation is appreciated :)
 
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  • #2
Don't you have a textbook?

Basically, you start from the definition of the coefficient of performance and use the 1st law to write it in terms of ##Q_C## and ##Q_H##, the heat coming from the cold reservoir and that going to the hot reservoir, respectively. Then, you use the 2nd law to translate ##Q_C## and ##Q_H## to ##T_C## and ##T_H##. This gives you the highest ##\beta## possible according to the 2nd law. Then you prove that a Carnot cycle working between ##T_C## and ##T_H## has a value of ##\beta## that is the highest possible. Therefore, ##\beta \le \beta(\mathrm{Carnot})##.
 

FAQ: Prove:β (heat pump) is always less or equal to β(Carnot HP)

How is β (heat pump) related to β (Carnot HP)?

The coefficient of performance (β) of a heat pump is always less than or equal to the Carnot coefficient of performance (β) because the Carnot cycle is the most efficient thermodynamic cycle, and any real-world system will have some energy loss and inefficiencies.

Can you provide a mathematical proof for this statement?

Yes, the mathematical proof involves comparing the equations for β (heat pump) and β (Carnot HP) and taking into account the Second Law of Thermodynamics, which states that no system can have a higher efficiency than a Carnot cycle.

Are there any exceptions to this rule?

No, there are no exceptions to this rule. The Second Law of Thermodynamics applies to all systems and ensures that the Carnot cycle is the upper limit of efficiency for any heat engine or heat pump.

How does this relate to real-world heat pumps?

In real-world heat pumps, there are always energy losses due to factors such as friction, heat transfer through insulation, and internal energy dissipation. These losses result in a lower coefficient of performance compared to the ideal Carnot cycle.

Does this mean that heat pumps are not very efficient?

No, this statement does not mean that heat pumps are not efficient. In fact, heat pumps are one of the most efficient ways to heat or cool a space since they transfer heat rather than create it. The statement simply means that they are not as efficient as the ideal Carnot cycle, which is a theoretical concept with no real-world applications.

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