- #1
Amer
- 259
- 0
Prove that the zeros and the poles of a meromorphic function dose not have a limit point
Solution:
Let P be the set of the poles of f suppose that it has a limit point.
p is a pole of f so it is an isolated point such that [tex]\lim_{z \rightarrow p} \mid f(z) \mid= \infty [/tex]
from isolated point definition there exist an R>0 such that f is analytic at the set B={z : 0<|z-p|<R }
but B is open and p in B, and B intersect U\{p} is not phi so f is not analytic at B
Contradiction
what about the set of zeros, and is my proof right ?
Solution:
Let P be the set of the poles of f suppose that it has a limit point.
p is a pole of f so it is an isolated point such that [tex]\lim_{z \rightarrow p} \mid f(z) \mid= \infty [/tex]
from isolated point definition there exist an R>0 such that f is analytic at the set B={z : 0<|z-p|<R }
but B is open and p in B, and B intersect U\{p} is not phi so f is not analytic at B
Contradiction
what about the set of zeros, and is my proof right ?