- #1
transgalactic
- 1,395
- 0
S={3/2,5/3,7/4,9/5,11/6 ...}
the formula for this series is S(n)=2n+1/n+1
the limit for it as n->infinity gives me 2
i show that 2 is upper bound
2n+1/n+1<2 => 2>1 (always true)
now i need to show that 2 is the "least upper bound".
if 2 is not the least upper bound then there is a certain "x" for which
2n+1/n+1<2-x (2-x is the least upper bound)
now they are doing some thing really odd
2-x<2n+1/n+1
why?
this move is illegal
2-x cannot be smaller
its supposed to be the "least upper bound"
??
the formula for this series is S(n)=2n+1/n+1
the limit for it as n->infinity gives me 2
i show that 2 is upper bound
2n+1/n+1<2 => 2>1 (always true)
now i need to show that 2 is the "least upper bound".
if 2 is not the least upper bound then there is a certain "x" for which
2n+1/n+1<2-x (2-x is the least upper bound)
now they are doing some thing really odd
2-x<2n+1/n+1
why?
this move is illegal
2-x cannot be smaller
its supposed to be the "least upper bound"
??