- #1
skeeterrr
- 14
- 0
Homework Statement
Prove for all real numbers x and y that [tex]2xy =< x^2 + y^2[/tex]
Homework Equations
The Attempt at a Solution
Well, since this is a problem regarding proof, I thought I would start with a contradictory statement like:
2xy >= x^2+y^2
0 >= x^2-2xy+y^2
0 >= (x-y)^2
Since (x-y)^2 is either a positive integer and a zero,
0 =< (x-y)^2
0 =< x^2-2xy+y^2
2xy =< x^2+y^2
Well that's all I can think of... can anyone point out any mistakes or anything? Is there more to it than just this?