- #1
Simfish
Gold Member
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f(x) is a function with...
[tex]| f(x) - f(y) | \leq |x-y|^2 \forall x,y \in \Re [/tex]
(a) prove differentiability in R, find f'
(b) prove f continuous
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my steps;
(a) [tex]\frac{| f(x) - f(y) |}{|x-y|} \leq |x-y|[/tex]
Then by the definition of differentiability as stated in Apostol "Mathematica Analysis pg. 104, f is differentiable if the limit of the function as x -> y exists.
So by the inequality, as x -> y, we know that the limit is bounded and therefore must exist. The value of the limit is simply |x-y|, so is that always the derivative of the function? (or could it be |x|)? Since the derivative, after all, must always be positive?
(b) differentiability implies continuity
[tex]| f(x) - f(y) | \leq |x-y|^2 \forall x,y \in \Re [/tex]
(a) prove differentiability in R, find f'
(b) prove f continuous
====
my steps;
(a) [tex]\frac{| f(x) - f(y) |}{|x-y|} \leq |x-y|[/tex]
Then by the definition of differentiability as stated in Apostol "Mathematica Analysis pg. 104, f is differentiable if the limit of the function as x -> y exists.
So by the inequality, as x -> y, we know that the limit is bounded and therefore must exist. The value of the limit is simply |x-y|, so is that always the derivative of the function? (or could it be |x|)? Since the derivative, after all, must always be positive?
(b) differentiability implies continuity