Proving a function is well defined and continuous

In summary, we are trying to prove that the series f(x) = \sum^{\infty}_{n=1} f_{n}(x) is well defined and continuous on the interval [0,1]. We are working in a complete normed space (C[0,1], || . ||_{∞}). We have considered the real series \sum^{∞}_{n=1}||f_{n}||_{∞}=\sum^{∞}_{n=1} sup <f_{n}(x) : x\in[0,1]>, but we need to show that \sum^{∞}_{n=1}|f_{n}| converges. Some suggested methods include
  • #1
mick25
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0

Homework Statement


Let [itex]f_{n}(x)=\frac{-x^2+2x-2x/n+n-1+2/n-1/n^2}{(n ln(n))^2}[/itex]

Prove [itex]f(x) = \sum^{\infty}_{n=1} f_{n}(x)[/itex] is well defined and continuous on the interval [0,1].

Homework Equations



In a complete normed space, if [itex]\sum x_{k}[/itex]converges absolutely, then it converges.

The Attempt at a Solution



Working in a complete normed space [itex](C[0,1], || . ||_{∞})[/itex],

consider the real series [itex]\sum^{∞}_{n=1}||f_{n}||_{∞}=\sum^{∞}_{n=1} sup <f_{n}(x) : x\in[0,1]> [/itex]

It just remains to show that [itex]\sum^{∞}_{n=1}|f_{n}|[/itex] converges, but I can't seem to figure out how. Could anyone help me out here?
 
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  • #2
some ideas i haven't tried them yet though... how about first separating n into some manageable pieces...

first evaluate the convergence of the terms only dependent on n, then consider the terms with an x and have a think about what x value will maximize that sum.

then if it's tough to pull it together you may want to consider some properties of the norm.

then I think you may need more for the continuous part and move to the epsilon deltas
 
  • #3
Rather than dealing with all the terms separately, I've been trying to just apply a simple comparison test (followed by an integral test) to prove its convergence, but I could only come up with divergent cases.

I'm starting to think if there is an error with this question; does this series converge if it starts at n=1?
 
  • #4
yeah as 1/ln(1)^2 is undefined
 

FAQ: Proving a function is well defined and continuous

What does it mean for a function to be well defined?

A function is well defined if each input has exactly one corresponding output. This means that for every possible input, the function produces a unique and unambiguous output.

How do you prove that a function is well defined?

To prove that a function is well defined, you must demonstrate that it produces a unique output for every possible input. This can be done by showing that the function follows a clear and consistent rule or formula, and that it does not produce any ambiguous or contradictory results.

What is the importance of proving that a function is well defined?

Proving that a function is well defined is important because it ensures that the function is reliable and consistent. It guarantees that for every input, the function will produce a unique and unambiguous output, which is essential for making accurate and meaningful calculations and predictions.

How is continuity related to the well-definedness of a function?

Continuity is closely related to the well-definedness of a function. A function can only be continuous if it is well defined, meaning that it produces a unique output for every input. If a function is not well defined, it cannot be continuous because it would have breaks or "jumps" in its graph.

What methods can be used to prove that a function is continuous?

There are several methods that can be used to prove that a function is continuous. These include the epsilon-delta definition, the intermediate value theorem, and the continuity of elementary functions. Additionally, a function can also be proven to be continuous if it is differentiable, as differentiability implies continuity.

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