- #1
JG89
- 728
- 1
I was trying to prove a limit, and I found that I can take [tex] \epsilon = \sqrt[]{13}(\sqrt[]{\delta + 1} - 1) [/tex] since as delta goes to 0, it's obvious that entire expression also goes to 0, so epsilon also goes to 0.
My question is, how is the rigorousness of this? Will it be good enough for a uni. prof? (I have no experience with them)
My question is, how is the rigorousness of this? Will it be good enough for a uni. prof? (I have no experience with them)