- #1
mjjoga
- 14
- 0
a) Suppose that the limit as n goes to infinity sn=0. If (tn) is a bounded sequence, prove that lim(sntn)=0.
So I need to show that abs(sntn)<epsilon, and I know that abs(sn)<epsilon. I mean, I know abs(sntn)=abs(sn)abs(tn that didn't help.
I don't know how to go about this. I've tried the triangle inequality variations but that didn't seem to get me anywhere either. I feel like I'm going in circles.
can I get a hint?
thanks!
So I need to show that abs(sntn)<epsilon, and I know that abs(sn)<epsilon. I mean, I know abs(sntn)=abs(sn)abs(tn that didn't help.
I don't know how to go about this. I've tried the triangle inequality variations but that didn't seem to get me anywhere either. I feel like I'm going in circles.
can I get a hint?
thanks!