- #1
egillesp
- 5
- 0
Hi,
I need help proving the following trig identity:
\(\displaystyle \frac{\cot^2(x)-\cot(x)+1}{1-2\tan(x)+\tan^2(x)}=\frac{1+\cot^2(x)}{1+\tan^2(x)}\)
Me and my friend have spent several hours determined to figure this out, starting from the left hand side, the right hand side, and doing both together, but nothing seems to work.
For example, I tried to factor the left hand side, \(\displaystyle \frac{(\cot(x)-1)^2}{(\tan(x)-1)^2}\), but it didn't get me anywhere.
Help would be greatly appreciated
I need help proving the following trig identity:
\(\displaystyle \frac{\cot^2(x)-\cot(x)+1}{1-2\tan(x)+\tan^2(x)}=\frac{1+\cot^2(x)}{1+\tan^2(x)}\)
Me and my friend have spent several hours determined to figure this out, starting from the left hand side, the right hand side, and doing both together, but nothing seems to work.
For example, I tried to factor the left hand side, \(\displaystyle \frac{(\cot(x)-1)^2}{(\tan(x)-1)^2}\), but it didn't get me anywhere.
Help would be greatly appreciated